4-Ethoxy-5-isopropyl-2-methyl-phenylamine, HCl
4-Ethoxy-5-isopropyl-2-methyl-phenylaminehydrochloride
CAS: 473704-48-2
Molecular Formula: C12H20ClNO
4-Ethoxy-5-isopropyl-2-methyl-phenylamine, HCl - Names and Identifiers
4-Ethoxy-5-isopropyl-2-methyl-phenylamine, HCl - Physico-chemical Properties
| Molecular Formula | C12H20ClNO |
| Molar Mass | 229.75 |
| Storage Condition | Room Temprature |
| Sensitive | Irritant |
| MDL | MFCD02173762 |
4-Ethoxy-5-isopropyl-2-methyl-phenylamine, HCl - Risk and Safety
| Hazard Symbols | Xi - Irritant |
| Hazard Class | IRRITANT |
4-Ethoxy-5-isopropyl-2-methyl-phenylamine, HCl - Introduction
(4-ethoxy-5-isopropyl-2-methyl aniline hydrochloride) is an organic compound, its chemical formula is C14H23ClNO.
Its properties include:
-Appearance: White to off-white crystal powder.
-Melting point: about 130-133°C.
-Solubility: It is less soluble in water, but soluble in some organic solvents such as ethanol and dichloromethane.
Its main uses include:
-Drug synthesis: It can be used as an intermediate in organic synthesis and used to prepare other pharmaceutical compounds.
-Chemical research: It can be used as a catalyst or substrate for organic synthesis reactions.
The preparation method can be prepared by the following steps:
1. It will react with hydrogen chloride gas to generate hydrochloride.
2. will react with sodium carbonate hydrochloride or sodium hydroxide to neutralize the solution to generate freebase.
3. Finally, the freebase will react with hydrochloric acid to get the fluorite.
Its properties include:
-Appearance: White to off-white crystal powder.
-Melting point: about 130-133°C.
-Solubility: It is less soluble in water, but soluble in some organic solvents such as ethanol and dichloromethane.
Its main uses include:
-Drug synthesis: It can be used as an intermediate in organic synthesis and used to prepare other pharmaceutical compounds.
-Chemical research: It can be used as a catalyst or substrate for organic synthesis reactions.
The preparation method can be prepared by the following steps:
1. It will react with hydrogen chloride gas to generate hydrochloride.
2. will react with sodium carbonate hydrochloride or sodium hydroxide to neutralize the solution to generate freebase.
3. Finally, the freebase will react with hydrochloric acid to get the fluorite.
Last Update：2024-04-09 21:50:46
